The SAT gives you a function and then asks about g of x equals f of x plus 3, or f of the quantity x minus 2, and wants to know how the graph moved. The rule is short but counterintuitive: changes inside the parentheses move the graph horizontally and in the opposite direction from what the sign suggests.
Changes outside the function move it vertically in the direction you expect. The graph of f of x plus 3 is the graph of f shifted up 3 units, since every output is 3 larger. The graph of f of x minus 6 is shifted down 6 units. If a question describes a curve moved up or down, look for the constant sitting outside.
Changes inside the parentheses move it horizontally and backward from the sign. The graph of f of the quantity x minus 2 is the graph of f shifted right by 2, not left. Here is why. If the original graph has an interesting point at x equals 0, the new function reaches that same interesting behavior when x minus 2 equals 0, which is at x equals 2. So the feature moved right even though the expression shows a minus.
Combine the two and the description stacks. If f of x equals x squared, then g of x equals the quantity x plus 4 squared minus 1 is the basic parabola shifted 4 units left and 1 unit down, putting its vertex at the point with coordinates negative 4 and negative 1. This is exactly vertex form, which is why the vertex sign rule and the transformation sign rule are the same fact.
A minus sign in front of the whole function reflects it across the x-axis, turning every output into its opposite. So negative f of x flips an upward parabola into a downward one. A minus sign attached to the input, as in f of negative x, reflects across the y-axis instead, swapping left and right.
A number multiplying the whole function stretches it vertically. In 3 times f of x, every output is tripled, so the graph is three times as tall at each input while the zeros stay in place, since tripling zero is still zero. A multiplier between 0 and 1 compresses the graph toward the horizontal axis instead. Testing one convenient input, often x equal to zero, is a fast way to confirm which choice matches.