StudyPebble

SAT Linear Equations With Fractions

Fractions make an otherwise easy one-variable equation feel slow and error-prone. The SAT knows this and writes equations with denominators on purpose. The fix is a single move at the start: multiply every term on both sides by the least common denominator so no fraction survives past line one.

The rule

Multiply every single term on both sides by the least common denominator before you do anything else.

Start with x over 3 plus x over 4 equals 14. The denominators are 3 and 4, so the least common denominator is 12. Multiply every term by 12. The first term becomes 4x, the second becomes 3x, and the right side becomes 168. Now the equation is 7x equals 168, so x equals 24. No fraction arithmetic happened at any point.

The word every is doing real work in that instruction. Students multiply the fraction terms and forget the whole-number term, which quietly changes the equation. In the example above, skipping the 14 would leave 7x equals 14 and an answer of 2, which is wrong by a factor of 12. Write the multiplier in front of each term before you simplify any of them.

When a whole expression sits over a denominator, keep it in parentheses. In the equation the quantity 2x minus 5 all over 4 equals 3, multiplying both sides by 4 gives 2x minus 5 equals 12, so 2x equals 17 and x equals 8.5. If instead the equation were the quantity 2x minus 5 all over 4 plus x over 2 equals 3, the least common denominator is 4, giving 2x minus 5 plus 2x equals 12, so 4x equals 17.

Decimals are the same problem wearing different clothes. An equation like 0.4x plus 1.2 equals 3.6 becomes far easier if you multiply every term by 10, giving 4x plus 12 equals 36 and x equals 6. Multiply by 10 for one decimal place, by 100 for two. The SAT calculator can handle decimals directly, but clearing them still reduces the number of keystrokes where a mistake can enter.

One caution: clearing denominators is legal only because you are multiplying both sides by the same nonzero number. If the variable itself appears in a denominator, you are dealing with a rational equation rather than a linear one, and any solution that makes a denominator zero has to be thrown out at the end.

The trap

Multiplying only the terms that are fractions and leaving the whole-number terms untouched, which changes the equation instead of clearing it.

Try it

Try one
Real question

The equation 3(x + 1) = 3x + 5 has how many solutions?

A theater sold 240 tickets in all, and the number of student tickets sold was 3 times the number of adult tickets sold. Each ticket cost $18. How many dollars did the theater collect from student tickets?

  • A) 60
  • B) 180
  • C) 1,080
  • D) 3,240 ✓

Why: If a is the number of adult tickets, then a + 3a = 240, so a = 60 and there are 180 student tickets. The student tickets brought in 180(18) = $3,240. Choice C is the money from adult tickets. Answering 60 means you gave the number of adult tickets rather than any dollar amount. Answering 180 means you gave the number of student tickets, not the money they brought in. Answering 1,080 means you used the 60 adult tickets instead of the 180 student tickets.

Practice more of these free

Questions students ask

What is the least common denominator and how do I find it?

It is the smallest number that every denominator in the equation divides into evenly. For 3 and 4 it is 12. For 6 and 8 it is 24. If you cannot see it, multiplying all the denominators together always works, it just gives you larger numbers to simplify at the end.

Can I just use the calculator instead of clearing fractions?

For a numeric answer, often yes. But many SAT questions ask you to rewrite an equation or solve for a variable in terms of other letters, and the calculator cannot do that for you. Clearing denominators is a habit that keeps working when the numbers are replaced by letters.

Guides that cover this

More on linear equations in one variable