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SAT Discriminant Questions Explained

When an SAT question asks how many distinct real solutions a quadratic has, or asks for the value of a constant that gives exactly one solution, it wants the discriminant. You never have to solve the equation. You only compute the piece under the square root in the quadratic formula and check its sign.

The rule

For ax squared plus bx plus c equals zero, the sign of b squared minus 4ac tells you whether there are two, one, or no real solutions.

Write the equation in the form ax squared plus bx plus c equals zero. The discriminant is b squared minus 4ac. If that value is positive, the quadratic has two distinct real solutions. If it is exactly zero, there is one real solution, sometimes called a double root. If it is negative, there are no real solutions, because the formula would ask for the square root of a negative number.

Try x squared plus 6x plus 5 equals zero. Here a is 1, b is 6, and c is 5, so the discriminant is 36 minus 20, which is 16. Positive, so two distinct real solutions. Compare with x squared plus 6x plus 9 equals zero, where the discriminant is 36 minus 36, which is zero, so exactly one solution. And x squared plus 6x plus 11 equals zero gives 36 minus 44, which is negative 8, so no real solutions.

The harder version puts an unknown in the coefficients. Given x squared plus kx plus 25 equals zero has exactly one real solution, set the discriminant to zero: k squared minus 4 times 1 times 25 equals zero, so k squared equals 100 and k is 10 or negative 10. Read the question carefully, because it often asks only for the positive value, and both numbers will be sitting in the choices.

Two setup details cause most of the errors. First, the equation must equal zero before you identify a, b, and c. If you are given 2x squared plus 3x equals 5, move the 5 over to get 2x squared plus 3x minus 5 equals zero, so c is negative 5 rather than 5. Second, b squared is always positive since squaring removes the sign, so a b of negative 7 contributes positive 49.

This idea also answers geometric questions in disguise. A parabola crosses the x-axis twice when the discriminant is positive, touches it once when the discriminant is zero, and never touches it when the discriminant is negative. And for a system made of a line and a parabola, substitute the line into the parabola, collect everything on one side, and the discriminant of that single quadratic tells you how many times the two graphs intersect.

The trap

Identifying a, b, and c before moving every term to one side, so a constant keeps the wrong sign in the calculation.

Try it

Try one
Real question
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The graph of y = f(x) is shown in the xy-plane. For which values of x is f(x) = 2?

What is the solution set of √x = x - 2?

  • A) No real solution
  • B) x = 1 and x = 4
  • C) x = 4 ✓
  • D) x = 1

Why: Square both sides: x = (x - 2)² = x² - 4x + 4, so x² - 5x + 4 = 0 and (x - 1)(x - 4) = 0. That gives candidates x = 1 and x = 4, and squaring can create roots that do not satisfy the original equation, so check both. For x = 4, √4 = 2 and 4 - 2 = 2, so it works; for x = 1, √1 = 1 but 1 - 2 = -1, so it fails. The answer x = 1 and x = 4 reports both candidates without the check. The answer x = 1 keeps the extraneous root and drops the valid one. The answer No real solution rejects x = 4, which does satisfy the equation.

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Questions students ask

Do I need to solve the quadratic to answer a discriminant question?

No, and you should not. The question asks only how many real solutions exist or what constant produces a given count. Computing b squared minus 4ac answers both in one line, while solving takes longer and adds chances for arithmetic mistakes.

What does it mean when a question says exactly one solution?

It means the discriminant equals zero, so the two solutions from the quadratic formula collapse into the same value. Graphically, the parabola touches the x-axis at exactly one point, which is its vertex.

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